21 lines
425 B
Python
21 lines
425 B
Python
i_00 = 1
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i_10 = 2
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i_01 = 3
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i_11 = 4
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# 1)
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i_new_bilinear = 0.2 * (0.7 * 1 + 0.3 * 2) + 0.8 * (0.7 * 3 + 0.3 * 4)
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i_new_nn = 3
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print(i_new_bilinear, i_new_nn)
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# 2)
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i_new_bilinear = 0 * (1 * 1 + 0 * 2) + 1 * (1 * 3 + 0 * 4)
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i_new_nn = 3
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print(i_new_bilinear, i_new_nn)
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# 3)
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i_new_bilinear = 0.5 * (0.5 * 1 + 0.5 * 2) + 0.5 * (0.5 * 3 + 0.5 * 4)
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i_new_nn = 4 # Multiple solutions! Here: Ceil
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print(i_new_bilinear, i_new_nn)
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