17 lines
498 B
Python
17 lines
498 B
Python
i_00 = 1 # New position: (x=0.5, y=0.5)
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i_10 = 2 # New position: (x=1.5, y=0.5)
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i_01 = 3 # New position: (x=0.5, y=1.5)
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i_11 = 4 # New position: (x=1.5, y=1.5)
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# 1)
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i_new_bilinear = 0.5 * (0.5 * 1 + 0.5 * 2) + 0.5 * (0.5 * 3 + 0.5 * 4)
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i_new_nn = 4 # Multiple solutions! Here: Ceil
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print(i_new_bilinear, i_new_nn)
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# 2)
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# This solution is depending on the border behaviour! If no border behaviour is defined, there is not bilinear solution!
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i_new_bilinear = ...
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i_new_nn = 1
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print(i_new_nn)
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